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## Homework Statement

is the function f(x) = (2x^2-x)/(x^2+x) even, odd, or neither?

## Homework Equations

f(-x)=f(x) = even

f(-x)=-f(x) = odd

f(-x)≠f(x)≠ -f(x)

## The Attempt at a Solution

f(x) = (2x^2-x)/(x^2+x)

f(-x)=(2(-x)^2+x)/((-x)^2+(-x))

f(-x) = (2x^2+x)/(x^2-x)

i think that's the right way to do it, but i don't know if it's even or odd.