Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Is Feynman's time-ordering prescription covariant?

  1. Jun 1, 2005 #1
    We all know that time-ordering depends on the choice of Lorentz frame. So my question is somewhat obvious....

    Please give me a hint on where to look up that problem, eg. why the S-matrix theory is covariant.

    I guess the time-ordering prescription is implicitly defined for each single Lorentz frame (relative times are specific to each frame), and therefore we'll have to adjust the ordering of the operators when applying Lorentz boosts -- thereby rendering the theory covariant in an obvious way. Is that correct?
     
  2. jcsd
  3. Jun 1, 2005 #2

    dextercioby

    User Avatar
    Science Advisor
    Homework Helper

    By definition,the S matrix is both unitary and has no problem with the time ordering.A covariant theory of the S matrix is given in the path integral approach,which,as you might know,is much simpler.

    Daniel.
     
  4. Jun 1, 2005 #3
    The derivation (along with the reason for invariance) is given in Landau & Lif****z's Quantum Electrodynamics, p. 283-286, if the OP wants further reference.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?