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Is GR built on a manifold?

  1. Jul 4, 2013 #1
    I understand that SR and GR should not be dependent on the coordinate system. But does GR depend on the existence of a manifold? As I recall, GR is formulated with a metric tensor. And tensors are only defined on manifold. Or is there a manifold independent GR?
     
    Last edited: Jul 4, 2013
  2. jcsd
  3. Jul 4, 2013 #2

    WannabeNewton

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