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Is H^DaggerH a dual space

  1. Jul 19, 2013 #1

    I have a related question to one I just posted:

    Is H^DaggerH a dual vector space, or perhaps a dual vector field? Could H^dagger exist independently of H, or are they considered a kind of pair?
  2. jcsd
  3. Jul 19, 2013 #2
    The Hamiltonian is a Hermitian operator, so by definition [itex] H^{\dagger} = H [/itex].
  4. Jul 19, 2013 #3
    Thanks, dipole... My question is probably not a very good one!!
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