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Forums
Physics
Quantum Physics
QM: I as an Observable & Its Eigenvectors & Eigenvalue
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[QUOTE="Marrrrrrr, post: 6015463, member: 618379"] So, hermitian linear operators represent observables in QM. I (a matrix whose elements are all 1) is certainly a hermitian linear operator. Does this mean that I represent a measurable property? If so, what do we call that property? Identity? Moreover, for any state-vector A, A would be an eigenvector of I with the eigenvalue of 1. What does this all mean? What are the physical meaning of I as an observable (if it is) and its eigenvectors and the eigenvalue? How can we 'measure' I to get the value 1? [/QUOTE]
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Forums
Physics
Quantum Physics
QM: I as an Observable & Its Eigenvectors & Eigenvalue
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