Calculating Ice Melt from Heat Generated by a 54kg Skater Skating at 6.4 m/s"

[Link]

A 54kg ice skater skating at 6.4 m/s stops. If 50% of the heat generated is transferred to the ice, calculate how much ice is melted.

My solution:

(54 x 6.4^2)/2 = 1106 J

1106 x 0.5 = 553 J

553 = m x 3.33 x 10^5 (3.33 x 10^5 is latent heat of fusion of ice)

m = 1.6 grams

It sounds too small to be true, can someone verify please?

 

[dextercioby]

If the unit for ice melting latent heat is J/Kg,then it's okay...

Why surprised??

Daniel.

 

[chroot]

Link,

You are correct.

- Warren

 

[HallsofIvy]

Hey, you can hardly expect the whole skating rink to melt just because one skater comes to a halt!

 

[Link]

lol thanks guys! I tend to doubt my calculations sometimes... I was expecting something on 10 grams