- #1

- 14

- 0

Sketch the graph of:

[tex]\sin\Theta[/tex] = [tex]\frac{\pi}{2}[/tex] - [tex]\Theta[/tex]

Now the graph (between 0 and pi) is symmetrical about the line

[tex]\Theta[/tex] = [tex]\frac{\pi}{2}[/tex]

So I can write the equation as

[tex]\sin\Theta[/tex] = [tex]\frac{\pi}{2}[/tex] + [tex]\Theta[/tex]

This will be a graph of [tex]\sin\Theta[/tex] pulled [tex]\frac{\pi}{2}[/tex] units to the left.

Is this reasoning correct?

If it is, would you do it a different way?

Thanks

Jeremy

(Noone wants a gmail invite?lol!)