Force on Dam: Height or Amount of Water?

In summary: What do you mean by "so little water"?A thin column of water.Suppose the "lake" extends only 6 inches upstream.Actually the other thread is about aquariums; they were discussing and aquarium 8 feet wide, 3 feet deep, and 6 feet "thick."...The pressure at the bottom is 3 * 62 186 pounds/ft^2 or 1.3 psi. Now imagine the "thickness" is 1/2 inch (instead of 6 feet). It now holds only 8*3*(0.5/12) = 1 cubic foot; 62 pounds of water. The "I don't believe it"
  • #1
peanutaxis
24
3
Just had this pondering: Does the force on a water dam depend merely on the height of the water column behind it or does it depend on the total amount of water behind it? For the same dam if I have a lake behind it that is just a few metres wide vs. having a vastly large lake behind it with the same height.

Initially I want to say that the pressure at any given depth is dependant on water height/column only, so the force on the dam would be the same no matter the size of the lake, But that doesn't feel right somehow...
 
Engineering news on Phys.org
  • #2
Only the hydrostatic pressure due to the height is important.
 
  • #3
peanutaxis said:
Initially I want to say that the pressure at any given depth is dependant on water height/column only, so the force on the dam would be the same no matter the size of the lake, But that doesn't feel right somehow...
Remember that Force is Pressure x Area. In your question you ask about "Force", but I think you really mean Pressure.

The length of the lake behind the dam would not matter, but the width of the lake at the dam (and hence the width of the dam) would change the total "Force" on the dam, but not the max pressure on the dam base. Does that help?
 
  • Like
Likes hutchphd and russ_watters
  • #4
Yes, thanks all.
 
  • Like
Likes berkeman
  • #5
I just read through an exhausting 11-page thread on another forum arguing this same question. There are a few participants who "just can't believe" a thin column of water will exert the same total force on the dam wall. The thread over there just bounces back and forth; "does..." "does not..."

So I came here looking for a convincing argument or approach to explain "how can so little water apply tons of force." Anyone have good pedagogical approach? Thanks!
 
  • Like
Likes russ_watters and Lnewqban
  • #6
@gmax137 Surely they must agree that the force the little bit of water at the very bottom exerts on the column above is ##A h \rho g##, and that the pressure at this depth is then ##h \rho g##. All that remains is to note that hydrostatic pressure is isotropic.
 
  • Like
Likes Lnewqban
  • #7
etotheipi said:
Surely they must agree
Yes... "but still, how can so little water..."

There is some confusion between pressure, force, total force on the wall.. Like I said, it is exhausting. I was hoping someone here had a good analogy, that would prompt a "flash of insight" for the guys on the other forum. Or maybe a simple demonstration used in a high-school physics class to show (seeing is believing).
 
  • Like
Likes etotheipi
  • #8
I see. Maybe you could try poking holes in straws of different diameter and showing that the speed of efflux of water at a specific depth of the hole (measured by lateral distance traveled before hitting the table) is unchanged.

Of course, the most unambiguous thing to do in the case of the dam of depth ##h## and width ##w## is just to compute the total force explicitly,$$\vec{F} = \iint_S p d\vec{A} = \left( \int_{0}^{w} \int_{0}^{h} \rho g y \, dy dx \right) \hat{n} = \frac{1}{2} \rho g h^2 w \hat{n}$$and noting that this is independent of how far the water extends backwards from the damn in the ##z## direction.
 
Last edited by a moderator:
  • #9
gmax137 said:
... There are a few participants who "just can't believe" a thin column of water will exert the same total force on the dam wall.

So I came here looking for a convincing argument or approach to explain "how can so little water apply tons of force."...
What do you mean by "thin column of water" and by "so little water"?
 
  • #10
Imagine that you have a lake 10 km long exerting a total force F on a dam. Build a new dam 1 km upstream of the existing dam (without changing the water level); does the force F change? Take all the water out of the 9 km long upstream lake, does the force F change?
 
  • Like
Likes sysprog, gmax137 and etotheipi
  • #11
Lnewqban said:
What do you mean by "thin column of water" and by "so little water"?
Suppose the "lake" extends only 6 inches upstream.

Actually the other thread is about aquariums; they were discussing and aquarium 8 feet wide, 3 feet deep, and 6 feet "thick." So it holds 8*3*6= 144 cubic feet of water; about 9000 pounds. The pressure at the bottom is 3 * 62 186 pounds/ft^2 or 1.3 psi. The force on the 8 x 3 wall is 8*3*186/2 =2200 pounds.

Now imagine the "thickness" is 1/2 inch (instead of 6 feet). It now holds only 8*3*(0.5/12) = 1 cubic foot; 62 pounds of water. The "I don't believe it" guys can't mentally get over 62 pounds of water ("so little") exerting 2200 pounds of force on the wall.

For what it's worth, they have gotten past the complication of surface tension and meniscus, etc. that would come into it if the "thickness" gets too thin. The conversation there agrees to leave that out as a complicating factor unrelated to the "I don't believe it" problem.
 
  • #12
gmax137 said:
Actually the other thread is about aquariums; they were discussing and aquarium 8 feet wide, 3 feet deep, and 6 feet "thick." So it holds 8*3*6= 144 cubic feet of water; about 9000 pounds. The pressure at the bottom is 3 * 62 186 pounds/ft^2 or 1.3 psi. The force on the 8 x 3 wall is 8*3*186/2 =2200 pounds.
Even easier to visualise with an aquarium: divide it in two with a sheet of glass, does the force on the walls magically halve?
 
  • Like
Likes sysprog, Ibix, russ_watters and 1 other person
  • #13
Place two different diameter vertical tubes next to each other. Join them at the bottom.
Pour water into one tube and notice the water settles to the same level in the two tubes.
 
  • Like
Likes russ_watters and pbuk
  • #14
Thank you.
Have those poor souls heard about the Pascal's barrel experiment? :smile:
Pascal%27s_Barrel.png


Either you dive 10 meters below the surface of Lake Ontario or 10 meters below the surface of a small water well, each one of your tympanic membranes will feel a pressure that is equivalent to 2 atmospheres.

Multiply that value by the area of that membrane that is in contact with water (or trapped air), and you will have the value of the uniformly distributed force that that column of water is exerting over each membrane.

Now, if you need to generate electricity, you want huge amounts of water to be available, because the power you can expect to obtain depends on the flow rate of water, besides the difference of heights between upstream and downstream the generator.

Please, see:
https://en.wikipedia.org/wiki/Hydroelectricity#Calculating_available_power

:cool:
 
  • Like
Likes sysprog, russ_watters and pbuk
  • #15
So it's pretty easy to come up with both thought experiments and practical demonstrations of hydrostatic pressure (or insert any other basic scientific concept), unfortunately there will always be people participating in exhausting 11 page threads on other forums for whom evidence is not enough.

They are beyond help, sometimes you have to just walk away.
 
  • Love
  • Like
Likes Tom.G and Lnewqban
  • #16
Stretch a sheet of cellophane across a reservoir just upstream of the dam. If the know-nothings are to be believed, the force from the lake side will vastly exceed that from the dam side and the cellophane will be pushed into the dam.

One wonders where the trapped water would go -- squirted skyward maybe?
 
  • #17
Thank you all for your thoughtful suggestions. Turns out, @pbuk is right about this. (Except that other thread is now up to 16 pages...)

pbuk said:
unfortunately there will always be people participating in exhausting 11 page threads on other forums for whom evidence is not enough.

They are beyond help, sometimes you have to just walk away.
 
  • Like
Likes Lnewqban
  • #18
jbriggs444 said:
Stretch a sheet of cellophane across a reservoir just upstream of the dam. If the know-nothings are to be believed, the force from the lake side will vastly exceed that from the dam side and the cellophane will be pushed into the dam.
And for the love of god, don't go swimming in a large pool -- you'll be crushed against the side of the pool!
 
  • Like
Likes Bystander, jbriggs444 and gmax137
  • #19
russ_watters said:
you'll be crushed against the side of the pool!

Unless you stand exactly in the center!

BoB
 
  • Like
Likes russ_watters
  • #20
There is one important issue that strongly affects the perception of danger, in this case. If your experiment with a small tube fails, all that happens is a splash of water and perhaps some glass in your eye. If a dam fails then the energy stored is significant. That is sort of obvious to someone looking at the dam (or imagining it) so they could think 'it must be more force'. Not for the first time, force and energy are mixed up.
 
  • Like
Likes Joe591, pbuk, jrmichler and 1 other person

1. What is the force on a dam?

The force on a dam is the total amount of pressure exerted on the dam by the water it is holding back.

2. Does the height of the dam affect the force on it?

Yes, the height of the dam directly affects the force on it. The higher the dam, the greater the force of the water pushing against it.

3. How does the amount of water affect the force on a dam?

The amount of water behind a dam also affects the force on it. The more water there is, the greater the force pushing against the dam.

4. Is the force on a dam constant?

No, the force on a dam is not constant. It can change depending on factors such as the height of the water, the weight of the water, and external forces such as wind and earthquakes.

5. Can the force on a dam be measured?

Yes, the force on a dam can be measured using various methods such as pressure sensors, strain gauges, and hydrostatic pressure calculations.

Similar threads

Replies
5
Views
1K
Replies
50
Views
3K
Replies
5
Views
1K
  • General Engineering
Replies
11
Views
2K
  • Mechanical Engineering
Replies
3
Views
854
  • Introductory Physics Homework Help
Replies
9
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
3K
Replies
13
Views
641
  • General Engineering
Replies
12
Views
5K
Replies
12
Views
2K
Back
Top