- #1
tandoorichicken
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We learned that the Maclaurin series for sin(x) was
[tex]\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1}}{(2n+1)!} [/tex]
Is the Maclaurin series for sin(2x) the same, except with x replaced by 2x?
[tex]\sum^{\infty}_{n=0} (-1)^n \frac{x^{2n+1}}{(2n+1)!} [/tex]
Is the Maclaurin series for sin(2x) the same, except with x replaced by 2x?