Mentz114 said:Let me rephrase the question. If we counted up all the spins in one instant, what is probability that it will be 1) and integer 2) an integer + 1/2 3) a real number ?
Thank you.Jazzdude said:Neither. The moon, or any other object with sufficiently many interacting degrees of freedom, is not in a spin eigenstate. Therefore the characterisation as boson or fermion doesn't apply.
The Moon is neither a boson nor a fermion. These terms refer to particles on the subatomic level, and the Moon is a celestial body consisting of a large number of atoms and molecules.
In astronomy, a boson refers to one of the two types of particles in the Standard Model of particle physics. Bosons have integer spin and follow Bose-Einstein statistics, and they are responsible for mediating fundamental forces such as electromagnetism and the strong and weak nuclear forces.
In astronomy, quantum spin refers to the intrinsic angular momentum of subatomic particles. It is a fundamental property of particles and is quantized, meaning it can only have certain discrete values. Spin plays a crucial role in determining the behavior and interactions of particles.
Quantum spin does not directly relate to the Moon. However, the particles that make up the Moon, such as protons and neutrons, have spin, and their behavior and interactions are influenced by this property.
No, the Moon cannot be in a superposition state. Superposition is a quantum phenomenon that occurs on the subatomic level, and the Moon is made up of a large number of particles that do not exhibit this behavior. The Moon follows classical mechanics and can only exist in one definite state at a time.