I am trying to solve a linear 1st order diff eq. I have found the integrating factor, and multiplied it through the equation, now expecting it to be exact. However, I can't get it into an easy to solve form.(adsbygoogle = window.adsbygoogle || []).push({});

After multiplying by the integrating factor I have :

(e^-3x) dy/dx - (3e^-3x) y = 6e^-3x I can't figure out how to get this into form. The schaum's book puts this in the form d/dx [ye^-3x)] = 6e^-3x. I see that if you use the product rule on ye^-3x you get the original, but i'm not sure how you figure out how to get the original to the second form. Is there a trick? Can my TI89 do it? Any help is greatly appreciated. I have a test tomorrow and i'm not doing terribly well. I understand the problem before and after this part, but not this transition.

thx.

-A

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# Is there an easy trick to this (getting into form)

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