The definition of Δ (difference,drop of) Electrostatic Potential Energy(adsbygoogle = window.adsbygoogle || []).push({}); (D E-PE)says it

'is the work done on a unit charge (e) to bring it from r to r1 (against the force) withconstant(without acceleration) velocity andextremely lowabsolute value of velocity (quasistatic, vanishingly small, etc..)

afaik, v must be steady not to create magnetic disturbances or the like.

It escapes me what would happen if value of v is , say, 1 cm/s. (constant)

(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exactD G-PE)

Could you explain this to me, possibly without formulas? I need only to grasp the general idea!

Thanks

(* to simplify discussion let's assume the following ideal conditions:

A positive charge in vacuum distant from Galaxies equivalent of GM (0.0000184 C?)at the origin r(o) and

one electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Is there any significant difference between Gravitational and Coulomb Force (/Δ PE)?

**Physics Forums | Science Articles, Homework Help, Discussion**