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## Main Question or Discussion Point

The definition of Δ (difference,drop of) Electrostatic Potential Energy

'is the work done on a unit charge (e) to bring it from r to r1 (against the force) with

It escapes me what would happen if value of v is , say, 1 cm/s. (constant)

(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exact

Could you explain this to me, possibly without formulas? I need only to grasp the general idea!

Thanks

(* to simplify discussion let's assume the following ideal conditions:

A positive charge in vacuum distant from Galaxies equivalent of GM (

one electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)

*(D E-PE)*says it'is the work done on a unit charge (e) to bring it from r to r1 (against the force) with

*constant*(without acceleration) velocity and*extremely low*absolute value of velocity (quasistatic, vanishingly small, etc..)*afaik*, v must be steady not to create magnetic disturbances or the like.It escapes me what would happen if value of v is , say, 1 cm/s. (constant)

(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exact

*D G-PE*)Could you explain this to me, possibly without formulas? I need only to grasp the general idea!

Thanks

(* to simplify discussion let's assume the following ideal conditions:

A positive charge in vacuum distant from Galaxies equivalent of GM (

*0.0000184 C*?)at the origin r(o) andone electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)

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