The definition of Δ (difference,drop of) Electrostatic Potential Energy(adsbygoogle = window.adsbygoogle || []).push({}); (D E-PE)says it

'is the work done on a unit charge (e) to bring it from r to r1 (against the force) withconstant(without acceleration) velocity andextremely lowabsolute value of velocity (quasistatic, vanishingly small, etc..)

afaik, v must be steady not to create magnetic disturbances or the like.

It escapes me what would happen if value of v is , say, 1 cm/s. (constant)

(We can shoot an electron in a G Field at 1 Km/ s without problems, and get exactD G-PE)

Could you explain this to me, possibly without formulas? I need only to grasp the general idea!

Thanks

(* to simplify discussion let's assume the following ideal conditions:

A positive charge in vacuum distant from Galaxies equivalent of GM (0.0000184 C?)at the origin r(o) and

one electron (e) at r = r(earth) = 6.4x 10^6 m moving to r1 at v= 1 cm (m, km?)/ s)

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# Is there any significant difference between Gravitational and Coulomb Force (/Δ PE)?

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