Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Calculus and Beyond Homework Help
Is this a valid approach to finding critical values of a trig function
Reply to thread
Message
[QUOTE="TitoSmooth, post: 4790951, member: 496474"] I was stuck for an hour trying to do this calculus 1 problem. Think I figured it out but it's a even problm. Find the absolute maximum and absolute minimum values of f on the given interval. f(t)=t+cot (t/2), [pie/4,7pie/4] f'=1-(1/2) csc^2 (t/2) So 1=1/2*csc^2 (t/2) 2=csc^2 (t/2) For some reason I didn't know what to to do with cc squared so I applied an identity. +/_ 1=cot (t/2) Took arc cot on both side. Arccot (+-1) =t/2 The arc cot gives me pie/4 and 3pie/4 So now I multiply both by 2. So I get pie/2=t or 3pie/2=t. Then I just plug the values in f and solve. To see which ones are global max n min including the endpoints. Also my question was. Are we allowed to take the inverse cot on both sides of Arccot (1)=arccot (cot^2 (t/2)) ? If so how would we work with it? I was thinking arccot1=1 and on the right side. Arccot will cancel one cot so I'm left with cot(t/2) Now 1=cot (t/2) Then I use pie/4 +pie (k)=t/2 and solve for solutions in the restricted interval? Is this correct [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Calculus and Beyond Homework Help
Is this a valid approach to finding critical values of a trig function
Back
Top