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Is this an even function?

  1. Dec 3, 2011 #1
    Am I correct in thinking exp(−x^2 ) is an even function?

  2. jcsd
  3. Dec 3, 2011 #2
    Yes! Do you see why?
  4. Dec 3, 2011 #3
    I think it's because if the x was replaced by (-x) you would have

    exp(−(-x)^2 ) = exp(-x^2) which is the same as the original function

    It's the same either with a +x or -x making it an even function.
  5. Dec 3, 2011 #4
    Indeed!! :smile:
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