set up a double integral to find the area of the region inside the cardioid r=2-2sin θ and outside the circle r=1.
The Attempt at a Solution
setting the two equations equal to each other, I got theta = pi/6 , 5pi/6
Area= ∫-5pi/6 to pi/6 ∫1 to 2-2sinθ rdrdθ
I am not sure if my bounds for the lower angle is correct or not.
any help is appreciated
here is the graph: