- #1

- Thread starter asi123
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You should use imageshack/other for images## Homework Statement

Guys, is this right?

And if it is, from the the y' got in there?

## Homework Equations

## The Attempt at a Solution

- #3

statdad

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The answer looks reasonable - perhaps multiply the two negatives.

I'm not sure what you mean by "And if it is, from the the y' got in there?"

- #4

HallsofIvy

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Here, z and y are both functions of some other variable, perhaps x or t. If z= f(y) and y is itself a function of x, then, by the chain rule

[tex]\frac{dz}{dx}= \frac{dz}{dy}\frac{dy}{dx}[/tex]

If, in particular, z= sin(1/y)= sin(y

[tex]\frac{dz}{dx}= cos(1/y)(-1/y^2)\frac{dy}{dz}[/tex]

or, the ' notation,

z'= cos(1/y)(-1/y

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