Is this equation correct

  • Thread starter gracy
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  • #1
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I have seen this in my book.Is this equation correct
##dW=F^→⋅dr^→##=##=-E^→.dr^→##
I don't think it is correct because ##dW=F^→⋅dr^→##
has unit of joule whereas ##- E^→.dr^→## it's unit is volt.
 
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  • #2
A.T.
Science Advisor
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I have seen this in my book.Is this equation correct
It's hard to read, but I think it misses charge. V*C=J
 
  • #3
Nugatory
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I have seen this in my book.Is this equation correct
##dW=F^→⋅dr^→##=##=-E^→.dr^→##
I don't think it is correct because ##dW=F^→⋅dr^→##
has unit of joule whereas ##- E^→.dr^→## it's unit is volt.
Any time the units don't balance you know something is wrong somewhere.

By the way, in Latex, \vec{E} will appear as ##\vec{E}##... Often useful when working with vectors.
 
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  • #4
jtbell
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And if you want to make a vector out of a single letter like E, the curly braces are optional. \vec E works just as well to produce ##\vec E##. You need the braces only when the symbol is more than one character, e.g. \vec {AB} gives you ##\vec {AB}##. \vec AB on the other hand gives you ##\vec AB##.
 
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  • #5
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/vec{F}
 
  • #6
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/vec{F}
 
  • #7
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##/vec{F}##
 
  • #8
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I am not able to write vectors.
 
  • #10
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\vec{F}
 
  • #12
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##\vec{F}## PERFECT!
 

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