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Calculus
Is this even possible? Question about Fourier Series....
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[QUOTE="Mark44, post: 5482280, member: 147785"] The Fourier series for sin(x) is, as you recognize, very simple, since the series would consist of one term. But your problem is not as simple, with the function being ##\sin(3x - x_0)##. Using the hint, this function can be written as ##\sin(3x)\cos(x_0) - \sin(x_0)\cos(3x)##, where ##\cos(x_0)## and ##\sin(x_0)## are constants. This expanded form makes it much simpler to find the coefficients of the terms in the Fourier series. [/QUOTE]
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Calculus
Is this even possible? Question about Fourier Series....
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