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## Main Question or Discussion Point

let be the inequality:

[tex][\frac{\Gamma(1/4-b/2-it/2)}{\Gamma(1/4+b/2+it/2)}]<\frac{\Gamma(1/4-b/2)}{\Gamma(1/4+b/2)} [/tex]

where [] means modulus of the complex number...

[tex][\frac{\Gamma(1/4-b/2-it/2)}{\Gamma(1/4+b/2+it/2)}]<\frac{\Gamma(1/4-b/2)}{\Gamma(1/4+b/2)} [/tex]

where [] means modulus of the complex number...