1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Is this possible to solve?

  1. Apr 1, 2008 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    3. The attempt at a solution

    Is this possible to solve?

    I don't think so.


    For whatever value of x, we can't get 0, right?
  2. jcsd
  3. Apr 1, 2008 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    you are correct. No value of x will make [itex]3^x= 0[/itex] so that equation has no solution.
  4. Apr 1, 2008 #3
    Ok, thank you.
  5. Apr 1, 2008 #4
    If we suppose that x is from the extended reals [tex]x\in[-\infty,+\infty][/tex],

    Could we say then that equations like [tex] a^{x}=0[/tex] have solution for [tex]x=-\infty, \ \ \ a\in R[/tex] ??
  6. Apr 2, 2008 #5
    It is true that [tex]\lim_{x\to-\infty}a^x = 0[/tex] when |a| > 1, but that is not the same as saying that [itex]x = -\infty[/itex].
  7. Apr 2, 2008 #6
    Yeah, i do understand this part, i was just wondering how does one perform opertations on the extended reals, that is [tex][-\infty,+\infty][/tex], rather than just in [tex](-\infty,+\infty)[/tex]
  8. Apr 2, 2008 #7


    User Avatar
    Staff Emeritus
    Science Advisor

    I'm not aware of any way of way of definining trig functions on the extended reals.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Is this possible to solve?
  1. Solve for A (Replies: 17)