# Is this proof of riemann hypothesis?

1. Feb 13, 2009

### epkid08

If

$$\lim_{\sigma \rightarrow c} \frac{d^2 \zeta}{dt^2} = L_t$$

and 0<c≠.5<1, then L is an ever increasing function of t, with initial conditions bounding that of any c, 0<c<1. Because L is ever increasing, bounding all c at zero, it can be said that regardless of t, ζ will never equal zero for any s = σ + it.

If

$$\lim_{\sigma \rightarrow c} \frac{d^2 \zeta}{dt^2} = L$$

and c=.5, then L is a constant function independent of the variable t, and because L is constant and not ever increasing, it leaves the opportunity open for ζ(s)=0 for some s.

(I of course would have to prove the two limits)

Last edited: Feb 13, 2009