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Is this right? chem

  1. Jun 18, 2005 #1
    Hi guys can you please check if this is right....thanks in advance

    Given the reaction CO2(g) + H2(g) = H2O(g) + CO(g). If initially there are 2.0 moles of CO2 (g) and 2.0 moles of H2(g) introduced into an empty 1.0L container, at 1800ºC, it is found that at equilibrium there are 0.3 moles of CO2 still present. Calculate the Ke value for this reaction at 1800ºC.

    CO2(g) + H2(g) = H2O(g) + CO(g)
    Initially 2 2 0 0
    Equilibrium 2-1.7=.3 2-1.7=.3 1.7 1.7


    Ke = 1.7 * 1.7/(.3 * .3) = 32.11
     
  2. jcsd
  3. Jun 18, 2005 #2
    can anyone help me out plz?
     
  4. Jun 18, 2005 #3
    I would try but I don't know what Ke is. Sorry.

    The Bob (2004 ©)

    P.S. Sorry this post was a waste of time.
     
  5. Jun 18, 2005 #4

    saltydog

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    Alright here goes JoeJo:

    This is the equilibrium expression for the reaction:

    [tex]CO_2+H_2\leftrightarrows H_2O+CO[/tex]

    [tex]K_c=\frac{[H_2O][CO]}{[CO_2][H_2]}[/tex]

    This at the concentrations at equilibrium which as you indicated, only 1.7 moles of both reagents reacted. So even though it would be nice if you formatted it nicely like I did, your answer looks Ok.
     
    Last edited: Jun 18, 2005
  6. Jun 18, 2005 #5
    lol thanks saltydog....i suck at latex...
     
  7. Jun 22, 2005 #6
    shouldn't the answer be 0.03
     
  8. Jun 22, 2005 #7
    JoeJo, your answer in #1 is corret, [itex]K_c=32.11[/itex]. How do you end up with 0.03?
     
  9. Jun 22, 2005 #8
    Kc=[H2O][CO] over [CO2][H2] = (0.3)^2 over (1.7)^2 = 0.03??


    am i right or wrong?
     
  10. Jun 23, 2005 #9
    Quote: "it is found that at equilibrium there are 0.3 moles of CO2 still present"
    What is [itex][CO_2]=[H_2]=?[/itex] at equilibrium? By the way you're correct about

    [tex]K_c=\frac{[H_2O][CO]}{[CO_2][H_2]}[/tex]
     
  11. Jun 23, 2005 #10
    [tex]K_c=\frac{[H_2O][CO]}{[CO_2][H_2]}[/tex]

    [tex]\frac{(0.3)^2}{(1.7)^2} [/tex]

    = 0.03
     
  12. Jun 23, 2005 #11
    isn't that right.....my first time with latex!!!
     
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