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Is this right so far? (Implicit diff.)

  1. Nov 5, 2012 #1
    tan(x-y)=y/(1+x2)

    When I take the derivatives of both sides, I get:
    sec2(x-y)(1-y')=[(1+x2)y'-2xy]/(1+x2)2
     
  2. jcsd
  3. Nov 5, 2012 #2

    tiny-tim

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