Can this be written.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

\[

\det{\textbf{A}}=a_{11}a'_{11}+a_{12}a'_{12}+\ldots+a_{1n}a'{1n}

\]

[/tex]

As. (Where I just use p instead of n for obvious reasons)

[tex]

\[

\sum^{n}_{p=1}{a_{1p}a'_{1p}}

\]

[/tex]

Since.

[tex]

\[

a'_{ij}=(-1)^{i+j}(\det{\textbf{A}_{ij}})

\]

[/tex]

And yes we are talking determinants.

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# Is this right?

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