1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Is this right?

  1. Mar 7, 2008 #1

    [tex]f(x)=-4x^2+4x \rightarrow f(x)=a(x-h)^2+k[/tex]


    [tex]f(x)=-4\left[x^2-x+\left(\frac 1 2\right)^2-\left(\frac 1 2\right)^2\right][/tex]

    [tex]f(x)=-4\left[x^2-x+\left(\frac 1 2\right)^2-\frac 1 4\right][/tex]

    [tex]f(x)=-4\left[x^2-x+\left(\frac 1 2\right)^2\right]+1[/tex]

    [tex]f(x)=-4\left(x-\frac 1 2\right)^2+1[/tex]
    Last edited: Mar 7, 2008
  2. jcsd
  3. Mar 7, 2008 #2


    User Avatar
    Homework Helper
    Education Advisor
    Gold Member

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook