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Is this the correct way to find the difference equation(nullingfilter)

  1. May 14, 2013 #1
    1. The problem statement, all variables and given/known data
    creating a nulling filter that filters the normalised radian frequency of (0.6pi )

    Find the difference equation?

    2. Relevant equations
    Do we use the exponential form or cosine form.
    Ae^j(wn + ∅)
    w=normalised frequency
    ∅ = phase angle

    3. The attempt at a solution
    y[n]=e^j(0.6*pi*n) xH( e^j(0.6*pi*n))
    H( e^j(0.6∏n))=1/2(1+e^-j(0.6*pi)

    H( e^j(0.6∏n))=Ʃbke^-j(0.6*pi*k)

    b0=1/2 and b1=1/2

    therefore is the difference equation
    y[n]= 1/2x[n]+1/2x[n-1]
  2. jcsd
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