1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Is this the correct way to find the difference equation(nullingfilter)

  1. May 14, 2013 #1
    1. The problem statement, all variables and given/known data
    creating a nulling filter that filters the normalised radian frequency of (0.6pi )

    Find the difference equation?




    2. Relevant equations
    Do we use the exponential form or cosine form.
    Ae^j(wn + ∅)
    A=amplitude
    w=normalised frequency
    ∅ = phase angle

    3. The attempt at a solution
    Therefore
    x[n]=e^j(0.6*pi*n)
    y[n]=e^j(0.6*pi*n) xH( e^j(0.6*pi*n))
    H( e^j(0.6∏n))=1/2(1+e^-j(0.6*pi)

    H( e^j(0.6∏n))=Ʃbke^-j(0.6*pi*k)

    b0=1/2 and b1=1/2

    therefore is the difference equation
    y[n]= 1/2x[n]+1/2x[n-1]
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?