Is this the correct way to find the difference equation(nullingfilter)

  • #1

Homework Statement


creating a nulling filter that filters the normalised radian frequency of (0.6pi )

Find the difference equation?




Homework Equations


Do we use the exponential form or cosine form.
Ae^j(wn + ∅)
A=amplitude
w=normalised frequency
∅ = phase angle

The Attempt at a Solution


Therefore
x[n]=e^j(0.6*pi*n)
y[n]=e^j(0.6*pi*n) xH( e^j(0.6*pi*n))
H( e^j(0.6∏n))=1/2(1+e^-j(0.6*pi)

H( e^j(0.6∏n))=Ʃbke^-j(0.6*pi*k)

b0=1/2 and b1=1/2

therefore is the difference equation
y[n]= 1/2x[n]+1/2x[n-1]
 

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