- #1

huan.conchito

- 44

- 0

**Please help me with Probability**

is this true in probability? P(AUB)' = (P(A) + P(B)) '

The question is

a) Assume that P(A) = 0.4 P(AnB)=0.1 P(A'nB')=0.2

P(B) = ?

what i did is:

P(AUB)= P(A)+P(B)- P(AnB)

P(AUB)= 0.4 + P(B)-0.1

P(A'nB')= 0.2 = P(AUB)' = 0.2 = 1 - (0.4 + P(B)-0.1)

P(B)= -0.5

NVM I GOT IT MYSELF

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