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## Homework Statement

Consider 1 gram of an ideal gas undergoing isobaric process. Suppose del(H) be the amount of heat given to it. Then,

del(H) = dU + del(W)

del(H) = 1 x C(v)dT + (P.dV)/J

But del(H) = C(p)dT

P.dV = r.dT

C(p)dT = C(v)dT + (r.dT)/J

C(p) - C(v) = r/J

## Homework Equations

## The Attempt at a Solution

In the above derivation, when volume is changing, how can they take dU = mC(v)dT?

Here m = mass of gas,r = gas constant,J = Mechanical equivalent of heat