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Isobaric Process

  • Thread starter traveler7
  • Start date
8
0
1. Homework Statement

Pf
429

Q
-754

ΔU
819

The table above shows the measurements taken while an ideal gas underwent an ISOBARIC process. Fill in the appropriate values for the table below.

ΔP=?



2. Homework Equations

Q= ΔU+W=ΔU=PΔV

3. The Attempt at a Solution

I dont know how to go about solving this
 

rock.freak667

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3. The Attempt at a Solution

I dont know how to go about solving this
For an isobaric process, what is constant? Hence what is ΔP ?
 

vela

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Do you know what isobaric means? If not, look it up.
 
8
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isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?
 

rock.freak667

Homework Helper
6,230
31
isobaric means same pressure

but i tried 429 and that didnt work

Is the difference in pressure 0? so 0 would be delta p?
Right so if it means the same pressure, then the final pressure and the initial pressure are the same. So the change in pressure would be 0.
 

vela

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It sounds like you're just guessing. You need to understand that the equations have meanings and the quantities that appear in them have precise definitions. If you don't know what ΔP represents, the first thing you need to do is figure that out.

In this case, ΔP=Pf-Pi represents the change in pressure between the initial and final states, so your answer of 429 (units?) would mean that the pressure increased by that amount. Clearly, this doesn't meet the condition of an isobaric process, where the pressure is, by definition, constant. Since the pressure is constant, you know that Pi=Pf, so ΔP=0.
 

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