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The function [itex]\frac{1}{\sin(\frac{\pi}{z})}[/itex] has isolated singularitiesat z=+-1, +-1/2, ....

However, it is said that it has annon-isolated singularityat z=0.

Anon-isolated singularityhas to be a point where its neigborhood too is also singular.

But, for some [itex]\epsilon > 0 ,\, \frac{1}{\sin(\frac{\pi}{\epsilon})}[/itex] is not singular eg. [itex]\epsilon = 0.000001 [/itex]

Can u pls explain.

Thanks

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# Isolated singularity

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