# Isosceles triangle

Strange... So what is the right answer now?

HallsofIvy
Homework Helper
But why 1-0 ? If the answer is P(1-0)/(1-1/4)=4P/3 then

$\frac{1}{{4}^{n+1}}=0$

because of $$P(1-\frac{1}{{4}^{n+1}})/(1-1/4)$$.

How is possible $${4}^{n+1}=0$$?

It isn't. Nor is $4^{-(n+1)}= 0$ for any fixed n. However, the limit $4^{-(n+1)}= 1/4^{n+1}= 0$ as n goes to infinity.

tiny-tim