Isosceles triangle

  • #26
Strange... :smile: So what is the right answer now?
 
  • #27
HallsofIvy
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But why 1-0 ? If the answer is P(1-0)/(1-1/4)=4P/3 then

[itex]\frac{1}{{4}^{n+1}}=0[/itex]

because of [tex]P(1-\frac{1}{{4}^{n+1}})/(1-1/4)[/tex].


How is possible [tex]{4}^{n+1}=0[/tex]?

It isn't. Nor is [itex]4^{-(n+1)}= 0[/itex] for any fixed n. However, the limit [itex]4^{-(n+1)}= 1/4^{n+1}= 0[/itex] as n goes to infinity.
 
  • #28
tiny-tim
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Strange... :smile: So what is the right answer now?

You tell us! :smile:
 

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