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I am a little bit confused about nuclear isospin.

u and d quarks have I = ½

u has I_3 = ½ , d has I_3 = -½ (third component)

right so far?

Now why does the proton have I = ½ and I_3 = 1/2, and

neutron I = ½ and I_3 = -1/2 ??

but when you add upp the I on the quark level , you might get things like 3/2 etc, has that something to do with the strong intreaction?

And how do one assign I and I_3 to p-bar and n-bar? [anti-proton, anti-neutron]

please help dear Nuclear and Particle lovers :)

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# Isospin question

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