Isothermal Expansion

  • Thread starter BlackMamba
  • Start date
  • #1
187
0
Hello,

I have what should be an easy problem, but I, of course, am having some issues.

Here's the problem: The temperature of 2 moles if an ideal gas is 380 K. How much work does the gas do in expanding isothermally to 3 times its initial volume?

So I know I'm gonna to need to use this equation to find the work done:
[itex]W = nRT ln (\frac{V_f}{V_i})[/itex]

I know that:

n = 2
R = 8.31
T = 380
Vi = (3)Vi
Vf = ?

I'm hung up on the volume portion of this problem. I don't have an initial or final volume and that's what I can't seem to work around. Any help would be greatly appreciated.

Thanks in advance.
 
Last edited:

Answers and Replies

  • #2
12
0
Vi = Vi
Vf = 3 Vi
since it expands three times its initial volume
 
  • #3
18
0
plz correct vi=3.vi to be vf=3 vi, so now the problem is solved..
 
  • #4
W = nRTln(3)

(Vf/Vi ) = 3Vi/Vi = 3
 
  • #5
187
0
Oh Lord. Something so simple that I couldn't put together. Thank you everyone for your reply. It is greatly appreciated. :)
 
  • #6
simple

:rofl:
BlackMamba said:
Hello,

I have what should be an easy problem, but I, of course, am having some issues.

Here's the problem: The temperature of 2 moles if an ideal gas is 380 K. How much work does the gas do in expanding isothermally to 3 times its initial volume?

So I know I'm gonna to need to use this equation to find the work done:
[itex]W = nRT ln (\frac{V_f}{V_i})[/itex]

I know that:

n = 2
R = 8.31
T = 380
Vi = (3)Vi
Vf = ?

I'm hung up on the volume portion of this problem. I don't have an initial or final volume and that's what I can't seem to work around. Any help would be greatly appreciated.

Thanks in advance.
vfinal=3vinitial
 

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