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## Homework Statement

A 2.00-mol sample of helium gas initially at 300K and 0.400 atm is compressed isothermally to 1.20atm. Assume the helium behaves as an ideal gas, find (a) the final volume of the gas, (b) the work done on the gas, and (c) the energy temperature?

## Homework Equations

PV = nRT

[tex]W = nRTln(\frac{Pi}{Pf})[/tex]

[tex]\delta{U} = Q - W[/tex]

## The Attempt at a Solution

This is what i have done can anyone tell me what is wrong, because it is not the same as the book's answer.

a)

[tex]Vf = \frac{2 * 8.314*10^3 * 300}{1.20}[/tex]

[tex]Vf = 4157000m^3[/tex]

b)

[tex]W = 2 * 8.314 * 10^3 * 300 * ln(\frac{1.20}{0.400})[/tex]

W = 5480317.541

c)

[tex]\delta{U} = -5480317.541[/tex] meaning this is compression

The correct answers for the following are:

a) 0.0410 [tex]m^3[/tex]

b) 5.48 kJ

c) -5.48 kJ

P.S