- #1

mcodesmart

- 34

- 0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter mcodesmart
- Start date

- #1

mcodesmart

- 34

- 0

- #2

Studiot

- 5,441

- 9

So if your property of interest is a member of a known group you can tell how many other members there are and if you have missed one out in you analysis or if there are any more to look for.

- #3

Simon_Tyler

- 313

- 1

E.g. all of the physical, regular crystals that can appear in nature must be finite subgroups of the rotation group. This allows for their complete classification.

Also Lie groups are indispensable.

Changes in your point of view of a system (i.e. Galilean, special and general relativity) must form a group. So that you can always make two changes to get another. You can always undo a change etc...

In relativistic field theory, if the field is to be obey special relativity, then it must be a representation of the Poincare group. If the field is to be fundamental (not phenomenological) then the representation must be irreducible. If we add quantum mechanics then it must be a unitary rep. If there are other fundamental (eg gauge/flavor) symmetries in the theory, then the field must also be an irrep of those.

This then gives us the classification of particles in quantum field theory.

http://en.wikipedia.org/wiki/Particle_physics_and_representation_theory

Then you get to technical issues, such as if you want a vector field in quantum field theory, then it must be a gauge field for a reductive (semisimple + U(1) factors) group.

- #4

AlephZero

Science Advisor

Homework Helper

- 7,025

- 297

- #5

dodo

- 695

- 2

- #6

Robert1986

- 828

- 2

So, a vector space forms a group. If you tell me this, I automatically know a lot of stuff about it. I know that you have defined some operation on it. I know that this operation has inverses. I know there is an identity element. I know that inverses are unique. I know that I can form subgroups. I know that if T is a homomorphism from V into itself then the kernel is a subgroup. I know that if the kernel is just {0} then the T is an isomorphism.

But, just wait till you get to higher algebra classes. You will see that a vector space, say R^3 forms something called an algebra. Then you can see that matrcies and linear transformations are all the same (well isomorphic.)

Also, a vector space is an algebraic structure in its own right. In fact, some texts define a vector space to be a group over a field of scalars. So, why do we characterize things as vector spaces? Well, we know a whole lot about vector spaces. Same with groups.

Share:

- Replies
- 12

- Views
- 1K

- Last Post

- Replies
- 3

- Views
- 211

- Replies
- 4

- Views
- 842

MHB
Group theory

- Last Post

- Replies
- 2

- Views
- 478

- Replies
- 38

- Views
- 981

- Last Post

- Replies
- 9

- Views
- 733

- Last Post

- Replies
- 4

- Views
- 544

- Last Post

- Replies
- 0

- Views
- 321

- Last Post

- Replies
- 2

- Views
- 546

MHB
Factor Group

- Last Post

- Replies
- 1

- Views
- 428