A 75 kg petty third wants to escape from a third story jail window. Unfortunately, a makeshift rope of sheets tied together can support a mass of only 50 kg. What is the minimal acceleration with which the thief must lower himself so he may use the "rope" without breaking it?(adsbygoogle = window.adsbygoogle || []).push({});

the variables i got were:

m=75 kg

a= -9.80m/s^2

v1=0

i then tried to use the formula for the thief, f=ma, isolated for a, a=f/m and substitued it into the rops max acceraltion limit, which formula is f=ma

i then got f(thief)/m(thief)= f(rope)/m, and i dont really know where to continue from there, because the thief must accelerate at a slower rate than what gravity plans for him, and must be a lower acceleration than 50 kg would normally fall right? please help!

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# Homework Help: Jail escape kinematics

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