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JK flip flop question.

  1. Dec 7, 2006 #1
    We're analyzing JK flip flop circuits and I don't understand it.

    So, Given that J = x, and K = xB' , my notes say that Q+ = JQ' + K'Q. I understand that. Then, substituting, we get xA' + x'A + xB.

    I have no idea how that final result was obtained. Can anyone help me with this?
     
  2. jcsd
  3. Dec 8, 2006 #2

    berkeman

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    Staff: Mentor

    Show and think about the circuit.
     
  4. Dec 8, 2006 #3
    K = x'B

    then what's the complement of K?

    K' = ?

    And look up the excitation tables.
     
    Last edited: Dec 8, 2006
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