Jones Calculus Question

  1. Is it by convention that the jones column vectors are written like,

    [1,i], [2,-i] etc etc, I never see [i,-2]

    Is [i,-1] really left circularly polarized light, it seems so indicated below

    [tex]\left[ \begin{array}{c} i \\ -1 \end{array} \right]\; =-i\; \left[ \begin{array}{c} ii \\ -1i \end{array} \right]\; =\; -i\left[ \begin{array}{c} i^{2} \\ -1 \end{array} \right]\; =\; -i\left[ \begin{array}{c} -1 \\ -1 \end{array} \right]\; =\; i\left[ \begin{array}{c} 1 \\ i \end{array} \right][/tex]
     
    Last edited: Mar 7, 2007
  2. jcsd
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