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Joule-Thompson experiment

  1. Sep 13, 2007 #1
    1. The problem statement, all variables and given/known data

    Show that the Joule-Thompson experiment is an isenthalpic process. (ΔH=0). The experimentally determined quantity is (Partial derivative T)/(Partial derivative P)H . Starting with the total differential for H, show that:

    (Partial deriv H)/(Partial deriv P)T = - Cp(Partial deriv T)/(Partial deriv P)H

    does anybody know even where to start ??, iam just confused with this question
     
  2. jcsd
  3. Sep 14, 2007 #2

    Kurdt

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    Do you know what the total differential of H is?
     
  4. Sep 14, 2007 #3
    no i dont, since i never took calc 3 and still having some hard time partial derivatives
     
  5. Sep 14, 2007 #4

    Kurdt

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    The total differential of H is:

    [tex] dH=C_p dT+ \left[ v - T \left( \frac{\partial v}{\partial T} \right) _p \right] dp [/tex]
     
    Last edited: Sep 14, 2007
  6. Sep 14, 2007 #5
    those this even seem right ??
     

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  7. Sep 16, 2007 #6

    Kurdt

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    If its isoenthalpic the dH is going to be zero. You're almost there.
     
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