Is the Joule-Thompson experiment an isenthalpic process?

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In summary, the conversation discusses the Joule-Thompson experiment and its relevance to isenthalpic processes. The experimentally determined quantity is the partial derivative of temperature with respect to pressure at constant enthalpy. This is then used to show that the partial derivative of enthalpy with respect to pressure at constant temperature is equal to negative the product of specific heat at constant pressure and the partial derivative of temperature with respect to pressure at constant enthalpy. The conversation also touches on the concept of total differentials and their relationship to partial derivatives.
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zeshkani
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Homework Statement



Show that the Joule-Thompson experiment is an isenthalpic process. (ΔH=0). The experimentally determined quantity is (Partial derivative T)/(Partial derivative P)H . Starting with the total differential for H, show that:

(Partial deriv H)/(Partial deriv P)T = - Cp(Partial deriv T)/(Partial deriv P)H

does anybody know even where to start ??, iam just confused with this question
 
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  • #2
Do you know what the total differential of H is?
 
  • #3
no i dont, since i never took calc 3 and still having some hard time partial derivatives
 
  • #4
The total differential of H is:

[tex] dH=C_p dT+ \left[ v - T \left( \frac{\partial v}{\partial T} \right) _p \right] dp [/tex]
 
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  • #5
those this even seem right ??
 

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  • #6
If its isoenthalpic the dH is going to be zero. You're almost there.
 

What is the Joule-Thompson experiment?

The Joule-Thompson experiment is an experiment in thermodynamics that involves the expansion of a gas through a porous plug or valve, causing it to cool or heat up.

What is the purpose of the Joule-Thompson experiment?

The purpose of the Joule-Thompson experiment is to study the properties of gases and their behavior under different conditions, such as pressure and temperature changes.

What is the Joule-Thompson coefficient?

The Joule-Thompson coefficient is a measure of how much a gas will cool or heat up when it undergoes an expansion or compression without any exchange of heat with its surroundings. It is denoted by the symbol μ.

What is the difference between the Joule-Thompson effect and the adiabatic process?

The Joule-Thompson effect involves a gas undergoing an expansion or compression while exchanging heat with its surroundings, resulting in a change in temperature. The adiabatic process, on the other hand, involves a gas undergoing a change in temperature without any heat exchange with its surroundings.

How is the Joule-Thompson effect used in real-world applications?

The Joule-Thompson effect is used in a variety of real-world applications, such as refrigeration systems, liquefaction of gases, and natural gas processing. It is also an important concept in the study of thermodynamics and gas dynamics.

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