Juggler Problem: Solving Kinematics for Ceiling Height

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In summary, if the ceiling is 1.5 m high and the juggler wants to juggle six balls, the ceiling should be at least 2.5 m high.
  • #1
student1ds
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A juggler can transfer a ball from his left hand to his right hand in 0.20 s. If he is juggling 5 balls and releases them from a height of 1.5 m, what is the minimum height of the ceiling? How much higher should the ceiling be if he wants to juggle 6 balls ?

How are we going to solve this? If we use kinematics equations, we could problem get through it, but I am not sure how to.
 
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  • #2
The first step is to figure out how long each ball spends in the air. (Not the 0.20 s part, but the part where the ball is tossed upward.)
 
  • #3
Doesn't seem like there's enough information regarding catch and throw times for the juggled balls. If the transfer from left to right hand is a toss (what most jugglers do), then it's possble for the juggler to do the left hand transfer toss before the right hand does the upwards toss, using the .2 second window of transfer toss time to switch between the upward toss and catching the ball from the transfer toss. Same goes for the left hand catching the next ball during the .2 second window transfer toss time. This would reduce the time between tosses. On the other hand, the time between tosses could be greater than the .2 second toss window time.

Perhaps the idea is to assume throw and catch time overhead is effectively zero, so that the time between all tosses is .2 seconds.
 
  • #4
rcgldr said:
Perhaps the idea is to assume throw and catch time overhead is effectively zero, so that the time between all tosses is .2 seconds.
That is how I am interpreting the problem.
 
  • #5
All the information required to solve the problem is present, provided one makes some common-sense assumptions, including that 0.20 s is the time from catching a ball with one hand to throwing the same ball with the other. Another assumption would be that he can throw one ball at the same moment he catches the one behind it.

Thus, 0.20 s is simply dwell time at the bottom, as well as the time between each of the balls in flight. The only kinematic equation required is the one for the vertical component.
 
  • #6
This might help in the visualization of the problem: http://www.flasharcade.com/arcade-games/juggling-simulator-game.html :)
 
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1. How does the ceiling height affect the solution to the Juggler Problem?

The ceiling height is a crucial factor in solving the Juggler Problem. It determines the maximum height that the juggler can reach with their throws, and therefore affects the overall difficulty of the problem.

2. What is the kinematics involved in solving the Juggler Problem?

Kinematics is the study of motion, and in the case of the Juggler Problem, it involves analyzing the trajectory of the juggler's throws and the height at which they catch the balls.

3. How can the Juggler Problem be solved mathematically?

The Juggler Problem can be solved using mathematical equations that take into account factors such as the velocity of the throws, the acceleration due to gravity, and the height of the ceiling. These equations can then be solved to determine the optimal throwing height for the juggler.

4. Are there any real-life applications of solving the Juggler Problem?

While the Juggler Problem may seem like a purely theoretical exercise, it has real-life applications in fields such as sports and robotics. For example, understanding the kinematics involved in juggling can help athletes improve their throwing and catching abilities, and solving the Juggler Problem can aid in the development of robots with advanced motor control.

5. Can the Juggler Problem be solved for different types of objects, such as rings or clubs?

Yes, the Juggler Problem can be solved for various types of objects as long as the same principles of kinematics and ceiling height are applied. The specific equations and solutions may vary depending on the shape and weight of the objects, but the overall concept remains the same.

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