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Jumping Problem

  1. Nov 29, 2006 #1
    Surprisingly, very few humans can jump more than 2 feet (0.6 m) straight up. Solve for the time one spends moving upward in a 2-foot vertical jump. Then double it for the "hang time" - the time one's feet are off the ground.
    b) Calculate the vertical height of Michael Jordan's jump when he attains a hang time of a full 1 s.

    a)
    t=sqrt(2d/g) =sqrt(2(0.6 m))/9.8 =0.35 s

    Hangtime=0.35 s x 2= 0.70 s

    b)
    d=(1/2)gt2=(1/2)(9.8 m/s2)(1.0 s)2= 4.9 m


    Is this correct?
     
  2. jcsd
  3. Nov 29, 2006 #2

    PhanthomJay

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    you forgot to divide the hang time by 2 in part b. part a is a ok.
     
    Last edited: Nov 29, 2006
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