In Cal, for the arctan(1/sqrt(3)), can I write it in degree or it's must be in radians?(adsbygoogle = window.adsbygoogle || []).push({});

here I have sqrt(3)*arctan(1/sqrt(3))-arctan(1)-integral (with the upper bound sqrt(3) and the lower bound 1) (x^3/(1+x^2)) dx

if I change it to degree

so I have 30sqrt(3)-45-1+(1/2)In2

But if it's in radians it would be sqrt(3)*Pi/g-Pi/4-1+(1/2)ln2

I got this pro wrong simple cuz I change that tan thing into degree.......but what's wrong with that?

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# Homework Help: Just a quick question

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