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1. The problem statement, all variables and given/known data

In this problem, you will apply kinematic equations to a jumping flea. Take the magnitude of free-fall acceleration to be 9.80 .

A flea jumps straight up to a maximum height of 0.550m . What is its initial velocity Vsub0 as it leaves the ground?

Express your answer in meters per second to three significant figures.

2. Relevant equations

Since my givens are

x = .550m

[Vsub0] = unknown

[Asubx] = =9.80

Hopefully [Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])

3. The attempt at a solution

[Vsubx]^2 = [Vsub0x]^2 + 2[Asubx] * (X-[Xsub0])

Vsubx is the final velocity, which at the max height is 0, and Xsub0 is just 0 as that's where it starts so I just plug the rest in

0^2 = [Vsub0x]^2 + 2[-9.80]*(.550)

0 = [Vsub0x]^2 -10.78

10.78 = [Vsub0x]^2

Sqrt(10.78) = 3.28 m/s

I think this is correct but i want to check as the homework system is somewhat unforgiving

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# Just Checking

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