Just two questions that are a small part of my ISU for physics. For this year we had to teach ourselves the unit on electricity and magnetism.

1. A bird stands on an electric tranmission line carrying 1200A. The line has a [itex]1.0\times10^{-5} \Omega[/itex] resistance per metre and the bird's feet are 30cm apart. What voltage does the bird feel.

2. What is the force per metre on a wirde carrying a 2.50A current when perpendicular to a 1.10T magenetic field.

For question one, I was first thinking that since the bird isn't grounded, it shouldn't really feel anything, but since the question probably wouldn't be as easy as that, i guess i'd have to calculate something.

Formula i used was just V=IR

[itex]V = (1200 A)(1.0\times10^{-5} \Omega)(3.0\times10^{-1}m)= 3.6 \times 10^{-3} V

[/itex]

That's what i got as a final answer

For question two, our books didn't really mention anything about formulas with the tesla unit so i guess we had to research it.

I found a formula that was :

[itex]B=\frac {F} {IL} \vspace[/itex]

B is 1.10T

I is 2.50 A

L i think would be 1m since they wanted the force per metre.

F is the unkown

So in the end i got [itex]F = BI

= 1.10T \times 2.50A =2.75 N/m

[/itex]

Just need some feedback on those questions.

1. A bird stands on an electric tranmission line carrying 1200A. The line has a [itex]1.0\times10^{-5} \Omega[/itex] resistance per metre and the bird's feet are 30cm apart. What voltage does the bird feel.

2. What is the force per metre on a wirde carrying a 2.50A current when perpendicular to a 1.10T magenetic field.

For question one, I was first thinking that since the bird isn't grounded, it shouldn't really feel anything, but since the question probably wouldn't be as easy as that, i guess i'd have to calculate something.

Formula i used was just V=IR

[itex]V = (1200 A)(1.0\times10^{-5} \Omega)(3.0\times10^{-1}m)= 3.6 \times 10^{-3} V

[/itex]

That's what i got as a final answer

For question two, our books didn't really mention anything about formulas with the tesla unit so i guess we had to research it.

I found a formula that was :

[itex]B=\frac {F} {IL} \vspace[/itex]

B is 1.10T

I is 2.50 A

L i think would be 1m since they wanted the force per metre.

F is the unkown

So in the end i got [itex]F = BI

= 1.10T \times 2.50A =2.75 N/m

[/itex]

Just need some feedback on those questions.

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