I just want to double check that this is right, i have a feeling it's wrong because 570 metres doesnt seem right(adsbygoogle = window.adsbygoogle || []).push({});

1. The problem statement, all variables and given/known data

A hot air ballon is floating above the surface of a small lake and, in the early morning breeze, is drifting at 5km/h horizontally. A 4.5 kg bag is dropped from the balloon when it is directly above a boat. The bag lands in the water 15m away from the boat. How high is the balloon?

2. Relevant equations

x-x0 = (v0costheta)t

and the vertical formula y-y0 = (vosintheta)-1/2gt^2

3. The attempt at a solution

I used the horizontal motion formula to find t

i used the initial velocity as 1.39m/s

x=15

and got t=10.79

then used the vertical formula to find y

which was y = 4.9 x 116.43 = 570

I just followed an example of horizontal and vertical motion in my text book

i think assuming the degree = 0 might of made my answer wrong or somthing

i kinda think that if the balloon was 570 the bag would of landed further than 15m

i apologize for my messiness

I also have another question, sorry im not very confident with physics because theres always somthing im not thinking about.

Question

In order to move a 300kg pallet of bricks across a smooth surface you need a rope tied to the back of your car. If the static friction is 0.2, how much tension is in the rope when the pallet just starts to move?

i just did 300 x 9.8 = 2940N

0.2 x 2940 = 588N

so is the required force to move the pallet 588+2940?

and the tension in the rope when it starts to move 588+2940?

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# Homework Help: Just want to doublecheck answers

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