- #1
- 123
- 0
I just want to double check that this is right, i have a feeling it's wrong because 570 metres doesn't seem right
1. Homework Statement
A hot air balloon is floating above the surface of a small lake and, in the early morning breeze, is drifting at 5km/h horizontally. A 4.5 kg bag is dropped from the balloon when it is directly above a boat. The bag lands in the water 15m away from the boat. How high is the balloon?
2. Homework Equations
x-x0 = (v0costheta)t
and the vertical formula y-y0 = (vosintheta)-1/2gt^2
3. The Attempt at a Solution
I used the horizontal motion formula to find t
i used the initial velocity as 1.39m/s
x=15
and got t=10.79
then used the vertical formula to find y
which was y = 4.9 x 116.43 = 570
I just followed an example of horizontal and vertical motion in my textbook
i think assuming the degree = 0 might of made my answer wrong or somthing
i kinda think that if the balloon was 570 the bag would of landed further than 15m
i apologize for my messiness
I also have another question, sorry I am not very confident with physics because there's always somthing I am not thinking about.
Question
In order to move a 300kg pallet of bricks across a smooth surface you need a rope tied to the back of your car. If the static friction is 0.2, how much tension is in the rope when the pallet just starts to move?
i just did 300 x 9.8 = 2940N
0.2 x 2940 = 588N
so is the required force to move the pallet 588+2940?
and the tension in the rope when it starts to move 588+2940?
1. Homework Statement
A hot air balloon is floating above the surface of a small lake and, in the early morning breeze, is drifting at 5km/h horizontally. A 4.5 kg bag is dropped from the balloon when it is directly above a boat. The bag lands in the water 15m away from the boat. How high is the balloon?
2. Homework Equations
x-x0 = (v0costheta)t
and the vertical formula y-y0 = (vosintheta)-1/2gt^2
3. The Attempt at a Solution
I used the horizontal motion formula to find t
i used the initial velocity as 1.39m/s
x=15
and got t=10.79
then used the vertical formula to find y
which was y = 4.9 x 116.43 = 570
I just followed an example of horizontal and vertical motion in my textbook
i think assuming the degree = 0 might of made my answer wrong or somthing
i kinda think that if the balloon was 570 the bag would of landed further than 15m
i apologize for my messiness
I also have another question, sorry I am not very confident with physics because there's always somthing I am not thinking about.
Question
In order to move a 300kg pallet of bricks across a smooth surface you need a rope tied to the back of your car. If the static friction is 0.2, how much tension is in the rope when the pallet just starts to move?
i just did 300 x 9.8 = 2940N
0.2 x 2940 = 588N
so is the required force to move the pallet 588+2940?
and the tension in the rope when it starts to move 588+2940?