- #1

asdf1

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i look at physics in my free time, and i just came across the rutherford scattering formula and was wondering is it necessary to memorize it?

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- Thread starter asdf1
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- #1

asdf1

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- 0

i look at physics in my free time, and i just came across the rutherford scattering formula and was wondering is it necessary to memorize it?

- #2

Gokul43201

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The important thing to take away from the formula is the [itex]1/(1-cos \theta)^2 [/itex] dependence of the scattering cross-section which is a signature of scattering from point-like objects.

- #3

asdf1

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the rutherford scattering formula is

N(cita)=(NntZ^2*e^4)/{[(8pi*epsilon)^2]*(E^2)sin^4(cita/2)} right?

because i don't see 1/[1-cos(cita)]^2...

- #4

jtbell

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Hint: browse through a list of trig identities.

- #5

asdf1

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so sin^4(cita/2)=[1-cos^2(cita)]/2={1-[1+cos(2cita)]/2}/2?

- #6

Gokul43201

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- #7

asdf1

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differential cross section? what's that?

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- #8

Gokul43201

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The differential cross-section is [itex]dN/d \Omega[/itex]

- #9

asdf1

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ok, thank you very much! :)

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