Just wondering

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  • #1
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i'm interested in physics, but i don't major in it...
i look at physics in my free time, and i just came across the rutherford scattering formula and was wondering is it necessary to memorize it?
 

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  • #2
Gokul43201
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Don't memorize it ! :eek:

The important thing to take away from the formula is the [itex]1/(1-cos \theta)^2 [/itex] dependence of the scattering cross-section which is a signature of scattering from point-like objects.
 
  • #3
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@@a
the rutherford scattering formula is
N(cita)=(NntZ^2*e^4)/{[(8pi*epsilon)^2]*(E^2)sin^4(cita/2)} right?
because i don't see 1/[1-cos(cita)]^2...
 
  • #4
jtbell
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Hint: browse through a list of trig identities. :wink:
 
  • #5
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so sin^4(cita/2)=[1-cos^2(cita)]/2={1-[1+cos(2cita)]/2}/2?
 
  • #6
Gokul43201
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Sorry, I didn't make this clear earlier. I was refering to the differential cross section. That's a more useful form of the scattering equation.
 
  • #7
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differential cross section? what's that?
@@
 
  • #8
Gokul43201
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It's the number of scattering events that go through an elemental area on the surface of a unit sphere centered on the scattering center. In spherical co-ordinates, an area element on the unit sphere (or an element of solid angle) is given by [itex]d \Omega = sin \theta d \theta d \phi [/itex].

The differential cross-section is [itex]dN/d \Omega[/itex]
 
  • #9
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ok, thank you very much! :)
 

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