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I ## k^0-\bar{k^0} ## mixing and gauge boson propagator

  1. Jan 23, 2017 #1
    Hi all ,

    I'm studying ## k^0-\bar{k^0} ## mixing from Cheng & Li's book "gauge_theory_of_elementary_particle_physics", page: 379 , I found that they consider the gauge boson propagator in the Feynman gauge, where
    ## i\Delta_{\mu\nu} = -i \frac{g_{\mu\nu}}{k^2-M^2_W} ## , but till my knowledge in this gauge the goldstone bosons remain in the theory, so why the contribution of the charged goldstone bosons for instance has not been taken into account in these calculation of the box diagram of ## k^0-\bar{k^0} ## like ## W^\pm## ?
     
  2. jcsd
  3. Feb 12, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
     
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