- #1

- 8

- 0

mass =1.3kg

41.5J

how do i get the velocity

so far i have it wrote like this

41.5J=1/2(1.3kg)(v)^2

but dont know how else to do plz help thanks ron

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- Thread starter truckerron1
- Start date

- #1

- 8

- 0

mass =1.3kg

41.5J

how do i get the velocity

so far i have it wrote like this

41.5J=1/2(1.3kg)(v)^2

but dont know how else to do plz help thanks ron

- #2

- 479

- 2

The equation KE=1/2mv^2 says that the kinetic energy is equal to half of the mass of the object times the object's velocity squared. So you need to solve for velocity (v). Isolate the v variable using algebra (try to get v by itself on one side of the equation).

Last edited:

- #3

- 29

- 0

KE=1/2mv^2

41,5J=1/2*1,3*v^2

41,5J/(1/2*1,3)=1/2*1,3*v^2/1/2*1,3

63,8=v^2

sqrt(63,8)=v

v=7,98 m/s

41,5J=1/2*1,3*v^2

41,5J/(1/2*1,3)=1/2*1,3*v^2/1/2*1,3

63,8=v^2

sqrt(63,8)=v

v=7,98 m/s

- #4

Integral

Staff Emeritus

Science Advisor

Gold Member

- 7,215

- 62

You will find that it is easier to do your algebra BEFORE plugging in the numbers. You have

[tex] \mbox{KE} = \frac 1 2 m v^2 [/tex]

then

[tex] 2 \mbox{KE} = m v^2 [/tex]

then

[tex] 2 \frac {\mbox{KE}} m = v^2 [/tex]

so

[tex] v = \sqrt { 2 \frac {\mbox{KE}} m } [/tex]

Now you can substitute in your numbers and arrive at the numeric solution.

[tex] \mbox{KE} = \frac 1 2 m v^2 [/tex]

then

[tex] 2 \mbox{KE} = m v^2 [/tex]

then

[tex] 2 \frac {\mbox{KE}} m = v^2 [/tex]

so

[tex] v = \sqrt { 2 \frac {\mbox{KE}} m } [/tex]

Now you can substitute in your numbers and arrive at the numeric solution.

Last edited:

- #5

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