- #1
CaptainSFS
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Homework Statement
A 15 kg uniform disk of radius R = 0.25 m has a string wrapped around it, and a m = 5 kg weight is hanging on the string. The system of the weight and disk is released from rest.
a) When the 5 kg weight is moving with a speed of 1.7 m/s, what is the kinetic energy of the entire system?
Homework Equations
v=[tex]\omega[/tex]R
I=[tex]\Sigma[/tex](m)(r)2
KE=(.5)(I)([tex]\omega[/tex])2
KEtotal = KEwheel + KEweight
The Attempt at a Solution
KE(wheel) = (.5)((15)(.25)2)((1.7)/(.25))2 = 21.675
+
KE(weight) = (.5)(5)(1.7)2 = 7.225
= 28.9 [This answer is incorrect though, I'm unsure as to what I'm doing incorrectly.]
Any help is much appreciated, thanks! :)