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kingyof2thejring
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how do you calculate the kintetic energy of the slowest emitted photoelectron? i know how to calculate the KE of the fastest emitted photoelectron.
The formula for calculating the KE of the slowest emitted photoelectron is KE = 1/2 * m * v^2, where m is the mass of the photoelectron and v is its velocity.
The mass of the photoelectron can be determined using the photoelectric effect, where the energy of the emitted electron is measured and the mass can be calculated using the equation E = h * f = m * v^2, where h is Planck's constant, f is the frequency of the incident light, and v is the velocity of the electron.
The KE of the slowest emitted photoelectron is typically measured in units of electron volts (eV) or joules (J).
The KE of the slowest emitted photoelectron is directly proportional to the energy of the incident light. This means that as the energy of the incident light increases, the KE of the emitted photoelectron will also increase.
The speed of the slowest emitted photoelectron will always be less than the speed of the incident light. This is because some of the energy of the incident light is used to overcome the binding energy of the electron in the material, leaving less energy available for the kinetic energy of the emitted electron.